In the 36th match of the Indian Premier League 2020, Mumbai was defeated by Mumbai Indians Vs Kings XI Punjab. KL Rahul's team got this victory after 2 superovers.
There have been more than one exciting match in the history of the Indian Premier League, but the kind of thrill fans have received on Sunday night has never happened before.
In the 36th match of IPL 2020, Kings XI Punjab won their third win in the tournament by defeating Mumbai Indians Vs Kings XI Punjab but they got this victory after not one but 2 super overs.
It was the first time in the IPL that a match resulted in two superovers. Let us tell you how KL Rahul's team defeated the strong army of Rohit Sharma.
The team of Mumbai Indians Vs Kings XI Punjab needed only 9 runs in the last over. Deepak Hooda and Chris Jordan were standing at the crease. On the first ball of Bolt, Hooda took a run and on the second ball Jordan turned the match towards Punjab, but after this Jordan was able to score just one run on the third ball and Hooda got the fourth ball.
On the fifth ball, Hooda scored one run. Punjab needed 2 runs on the last ball but Jordan was run out taking the second run. In this way, the match was tied and went to the super over.
You will be surprised to know that the first super over was also tied between Mumbai and Punjab. Mumbai handed the ball to Jasprit Bumrah and Punjab brought Puran and Captain Rahul to the crease.
First ball - Rahul could only take 1 run on a great yorker.
Second ball - Nicholas Pooran caught out on full-ball. Supt Roy caught his good catch.
Third ball - Bumrah gave Rahul a chance to take the same run on the third ball as well.
Fourth ball - Deepak Hooda could score only one run. In this way, Punjab had 4 runs in four balls.
the fifth ball, Rahul scored two runs and on the last ball he was out LBW on Bumrah's yorker. In this way, Mumbai got the target of only 6 runs.
First Super Over - Shami gets the ball
Punjab gave the responsibility of saving 6 runs to fast bowler Mohammad Shami. In front of Shami, Mumbai captain Rohit Sharma and wicketkeeper Quinton Dickock came.
First ball - Shami threw the yorker outside the off stump and Dickock could score a single run.
Second ball - This ball was also a yorker and Rohit's bat also got the same run.
Third ball - Shami once again threw a wide yorker, on which Dickock could score a single run.
Fourth ball- Shami did not allow Rohit Sharma to score a single yorker throw.
Fifth ball- Rohit could score a single run on another yorker from Shami. LBW appealed but was rejected by the umpire. Rohit was not found out in DRS.
Sixth ball - Mumbai had to score two runs off 1 ball. Quinton de Kock hit the ball outside the off-stump towards the covers and after taking the first run, when he ran for another, Rahul was run out on the best throw. In this way, the superover was also tied and then another super over.
Second super over
According to ICC rules, batsmen who had played in the first super over could not come to the crease in the second super over. Also, bowlers used in the first super over cannot bowl in the second super over.
Just from here the game started leaning towards Punjab. In the second super over, Mumbai batted first and the Pandya-Pollard pair landed at the crease. Punjab handed the bowling to Chris Jordan.
Mumbai innings (second super over)
First ball - Chris Jordan allowed Pollard to score just one run off the first ball.
Second ball - Jordan bowled the second ball wide outside the off-stump. After this, he let the yorker throw Pandya out of the off stump to take a single run.
Third ball - Jordan's attempt to throw the yorker failed and Low Fultos hit Pollard for a four.
Fourth ball - Jordan bowled another wide. Pollard then allowed Jordan to score a single run. Hardik Pandya runs out trying to take a second run.
Fifth ball- Pollard was dismissed by Jordan off the off-stump. The Mumbai player used DRS and was found not out. However, Mumbai did not get any runs.
Pollard took 2 runs off the sixth ball. In this way, Mumbai scored 11 runs in the super over. Punjab got a target of 12 runs to win.
Second Super Over (Punjab batting)
For the win, Punjab this time fielded Mayank Agarwal and T20 king Chris Gayle. Mumbai gave the responsibility of saving the run to Trent Boult.
First ball - Chris Gayle put a long six on the first ball. Bolt tried to throw the yorker, but it fell full and Gayle rode a six over long-on.
Second ball- Bolt threw a great bouncer and Gayle could score a single run.
Third ball- Bolt tries to throw the yorker once again and Mayank Agarwal hits the covers
On the fourth ball, Mayank Agarwal hit Punjab on the leg side and gave Punjab the victory in the second super over. With this victory, Punjab got two points.